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Re: [time-nuts] Q/noise of Earth as an oscillator

DK
Dan Kemppainen
Wed, Jul 27, 2016 7:15 PM

On 7/27/2016 10:04 AM, time-nuts-request@febo.com wrote:

Exciting the Earth with a new frequency (and an adeguate amount of
energy) sets a new rotational speed: you cannot retune a (for example)
quartz crystal in the same way...

Sure you can. Spin it at 100 RPM, or 1000, RPM or even 25000  RPM... :)

Interesting conversation. I tend to agree the earth is not a classic
harmonic oscillator. Energy is not exchanged between different storage
mechanisms. It's rotational period has no natural harmonic frequency.
i.e. rotational period could be anything.

However I also agree it exhibits characteristics of other items that Q
can be calculated for. Rate of slowing, loss of energy per cycle, etc.
And since the definition of Q is varied and used quite widely, it seems
Q is also appropriate here.

Maybe Earth is a special case since after all it DID give us the second,
and we DO set our atomic clocks to IT every 6 to 12 months...

...now I'll be thinking of this all night...  ...I think Tom is just
toying with us now...

Dan

On 7/27/2016 10:04 AM, time-nuts-request@febo.com wrote: > Exciting the Earth with a new frequency (and an adeguate amount of > energy) sets a new rotational speed: you cannot retune a (for example) > quartz crystal in the same way... Sure you can. Spin it at 100 RPM, or 1000, RPM or even 25000 RPM... :) Interesting conversation. I tend to agree the earth is not a classic harmonic oscillator. Energy is not exchanged between different storage mechanisms. It's rotational period has no natural harmonic frequency. i.e. rotational period could be anything. However I also agree it exhibits characteristics of other items that Q can be calculated for. Rate of slowing, loss of energy per cycle, etc. And since the definition of Q is varied and used quite widely, it seems Q is also appropriate here. Maybe Earth is a special case since after all it DID give us the second, and we DO set our atomic clocks to IT every 6 to 12 months... ...now I'll be thinking of this all night... ...I think Tom is just toying with us now... Dan
NM
Neville Michie
Thu, Jul 28, 2016 3:10 AM

The discussion of Earth as a system with Q, but which is not resonant,
is a more extreme case than the CONICAL PENDULUM.

The conical pendulum has a simple form of a weight on a string, instead of oscillating
in one plane as a conventional pendulum, it swings around in a circular orbit
in the horizontal plane. It has a definite resonant frequency.
Now a simple pendulum oscillates kinetic energy and potential energy, but a conical pendulum
has constant potential energy and oscillates its energy from North-South energy to East-West
energy.
I believe that a conical pendulum still has the circular error associated with amplitude.

But will it be as good a time keeper as the simple pendulum?

A curious fact about the conical pendulum is that whereas the simple pendulum has earth
rotation forces that show in the Foucault Pendulum, the conical pendulum has a different
period depending whether is swings clockwise or anticlockwise due to the earths rotation.

What do you think?

Cheers,
Neville Michie

The discussion of Earth as a system with Q, but which is not resonant, is a more extreme case than the CONICAL PENDULUM. The conical pendulum has a simple form of a weight on a string, instead of oscillating in one plane as a conventional pendulum, it swings around in a circular orbit in the horizontal plane. It has a definite resonant frequency. Now a simple pendulum oscillates kinetic energy and potential energy, but a conical pendulum has constant potential energy and oscillates its energy from North-South energy to East-West energy. I believe that a conical pendulum still has the circular error associated with amplitude. But will it be as good a time keeper as the simple pendulum? A curious fact about the conical pendulum is that whereas the simple pendulum has earth rotation forces that show in the Foucault Pendulum, the conical pendulum has a different period depending whether is swings clockwise or anticlockwise due to the earths rotation. What do you think? Cheers, Neville Michie
AP
Alex Pummer
Thu, Jul 28, 2016 4:43 AM

in case the Earth, the circular frequency of the Earth is equal of a
sinusoidal wave's frequency, which is a projection of the Earth circular
movement in a plain, which is perpendicular to the axis of the Earth.
The Q of the Earth in interpreted as the quotient of the phase speed of
the  Earth's  circular rotation [or the projected wave's] and the
fluctuation of the phase speed.

73
KJ6UHN
Alex

On 7/27/2016 8:10 PM, Neville Michie wrote:

The discussion of Earth as a system with Q, but which is not resonant,
is a more extreme case than the CONICAL PENDULUM.

The conical pendulum has a simple form of a weight on a string, instead of oscillating
in one plane as a conventional pendulum, it swings around in a circular orbit
in the horizontal plane. It has a definite resonant frequency.
Now a simple pendulum oscillates kinetic energy and potential energy, but a conical pendulum
has constant potential energy and oscillates its energy from North-South energy to East-West
energy.
I believe that a conical pendulum still has the circular error associated with amplitude.

But will it be as good a time keeper as the simple pendulum?

A curious fact about the conical pendulum is that whereas the simple pendulum has earth
rotation forces that show in the Foucault Pendulum, the conical pendulum has a different
period depending whether is swings clockwise or anticlockwise due to the earths rotation.

What do you think?

Cheers,
Neville Michie


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No virus found in this message.
Checked by AVG - www.avg.com
Version: 2016.0.7690 / Virus Database: 4627/12697 - Release Date: 07/28/16

in case the Earth, the circular frequency of the Earth is equal of a sinusoidal wave's frequency, which is a projection of the Earth circular movement in a plain, which is perpendicular to the axis of the Earth. The Q of the Earth in interpreted as the quotient of the phase speed of the Earth's circular rotation [or the projected wave's] and the fluctuation of the phase speed. 73 KJ6UHN Alex On 7/27/2016 8:10 PM, Neville Michie wrote: > The discussion of Earth as a system with Q, but which is not resonant, > is a more extreme case than the CONICAL PENDULUM. > > The conical pendulum has a simple form of a weight on a string, instead of oscillating > in one plane as a conventional pendulum, it swings around in a circular orbit > in the horizontal plane. It has a definite resonant frequency. > Now a simple pendulum oscillates kinetic energy and potential energy, but a conical pendulum > has constant potential energy and oscillates its energy from North-South energy to East-West > energy. > I believe that a conical pendulum still has the circular error associated with amplitude. > > But will it be as good a time keeper as the simple pendulum? > > A curious fact about the conical pendulum is that whereas the simple pendulum has earth > rotation forces that show in the Foucault Pendulum, the conical pendulum has a different > period depending whether is swings clockwise or anticlockwise due to the earths rotation. > > What do you think? > > Cheers, > Neville Michie > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there. > > > ----- > No virus found in this message. > Checked by AVG - www.avg.com > Version: 2016.0.7690 / Virus Database: 4627/12697 - Release Date: 07/28/16
TF
Tony Finch
Thu, Jul 28, 2016 10:50 AM

Neville Michie namichie@gmail.com wrote:

The conical pendulum has a simple form of a weight on a string, instead
of oscillating in one plane as a conventional pendulum, it swings around
in a circular orbit in the horizontal plane. It has a definite resonant
frequency.

I don't think it does have a resonant frequency, any more than the Earth
does: the angular velocity of the pendulum is sqrt(g/h) where h is the
height of the pendulum; give it more energy, it swings higher, so h is
smaller, so the frequency is higher.

Tony.

f.anthony.n.finch  dot@dotat.at  http://dotat.at/  -  I xn--zr8h punycode
South Thames, Dover: Southwesterly 5 or 6. Slight or moderate. Rain or
showers. Good, occasionally poor.

Neville Michie <namichie@gmail.com> wrote: > The conical pendulum has a simple form of a weight on a string, instead > of oscillating in one plane as a conventional pendulum, it swings around > in a circular orbit in the horizontal plane. It has a definite resonant > frequency. I don't think it does have a resonant frequency, any more than the Earth does: the angular velocity of the pendulum is sqrt(g/h) where h is the height of the pendulum; give it more energy, it swings higher, so h is smaller, so the frequency is higher. Tony. -- f.anthony.n.finch <dot@dotat.at> http://dotat.at/ - I xn--zr8h punycode South Thames, Dover: Southwesterly 5 or 6. Slight or moderate. Rain or showers. Good, occasionally poor.
JP
Jim Palfreyman
Thu, Jul 28, 2016 10:39 PM

Hi All,

Tom gave me a nudge to look here - I hadn't been following this thread.

For those that don't know, I study pulsars and so the way we measure what
pulsars do could be relevant to this discussion.

First, I have never heard of a Q measure when referencing a pulsar. I think
the key here is that it's not resonating as such. Rotating yes, resonating
no.

Pulsars spin and slow down due to giving off energy (magnetic dipole
radiation). So in the pulsar world we mainly refer to spin frequency (F0)
and frequency derivative (F1). With some of the younger and more "erratic"
pulsars, F2 (and further) can be modelled.

Here's some data on the Vela pulsar (hot off the presses - measured just
now):

F0              11.1867488542579
F1              -1.55859177352837e-11
F2              1.23776878287221e-21

Vela is young and erratic. Millisecond pulsars are outstanding clocks.
Here's the data for J0437-4715 - one of the most stable pulsars we know
about:

F0              173.6879458121843
F1              -1.728361E-15

I'm sure the "Q" of Vela would be pretty decent - but I can tell you now,
as a time-keeper, she's useless.

Jim Palfreyman

On 28 July 2016 at 20:50, Tony Finch dot@dotat.at wrote:

Neville Michie namichie@gmail.com wrote:

The conical pendulum has a simple form of a weight on a string, instead
of oscillating in one plane as a conventional pendulum, it swings around
in a circular orbit in the horizontal plane. It has a definite resonant
frequency.

I don't think it does have a resonant frequency, any more than the Earth
does: the angular velocity of the pendulum is sqrt(g/h) where h is the
height of the pendulum; give it more energy, it swings higher, so h is
smaller, so the frequency is higher.

Tony.

f.anthony.n.finch  dot@dotat.at  http://dotat.at/  -  I xn--zr8h
punycode
South Thames, Dover: Southwesterly 5 or 6. Slight or moderate. Rain or
showers. Good, occasionally poor.


time-nuts mailing list -- time-nuts@febo.com
To unsubscribe, go to
https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts
and follow the instructions there.

Hi All, Tom gave me a nudge to look here - I hadn't been following this thread. For those that don't know, I study pulsars and so the way we measure what pulsars do could be relevant to this discussion. First, I have never heard of a Q measure when referencing a pulsar. I think the key here is that it's not resonating as such. Rotating yes, resonating no. Pulsars spin and slow down due to giving off energy (magnetic dipole radiation). So in the pulsar world we mainly refer to spin frequency (F0) and frequency derivative (F1). With some of the younger and more "erratic" pulsars, F2 (and further) can be modelled. Here's some data on the Vela pulsar (hot off the presses - measured just now): F0 11.1867488542579 F1 -1.55859177352837e-11 F2 1.23776878287221e-21 Vela is young and erratic. Millisecond pulsars are outstanding clocks. Here's the data for J0437-4715 - one of the most stable pulsars we know about: F0 173.6879458121843 F1 -1.728361E-15 I'm sure the "Q" of Vela would be pretty decent - but I can tell you now, as a time-keeper, she's useless. Jim Palfreyman On 28 July 2016 at 20:50, Tony Finch <dot@dotat.at> wrote: > Neville Michie <namichie@gmail.com> wrote: > > > The conical pendulum has a simple form of a weight on a string, instead > > of oscillating in one plane as a conventional pendulum, it swings around > > in a circular orbit in the horizontal plane. It has a definite resonant > > frequency. > > I don't think it does have a resonant frequency, any more than the Earth > does: the angular velocity of the pendulum is sqrt(g/h) where h is the > height of the pendulum; give it more energy, it swings higher, so h is > smaller, so the frequency is higher. > > Tony. > -- > f.anthony.n.finch <dot@dotat.at> http://dotat.at/ - I xn--zr8h > punycode > South Thames, Dover: Southwesterly 5 or 6. Slight or moderate. Rain or > showers. Good, occasionally poor. > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there. >
AB
Azelio Boriani
Fri, Jul 29, 2016 7:33 AM

What about an ADEV/TDEV plot of the pulsar J0437-4715?

On Fri, Jul 29, 2016 at 12:39 AM, Jim Palfreyman jim77742@gmail.com wrote:

Hi All,

Tom gave me a nudge to look here - I hadn't been following this thread.

For those that don't know, I study pulsars and so the way we measure what
pulsars do could be relevant to this discussion.

First, I have never heard of a Q measure when referencing a pulsar. I think
the key here is that it's not resonating as such. Rotating yes, resonating
no.

Pulsars spin and slow down due to giving off energy (magnetic dipole
radiation). So in the pulsar world we mainly refer to spin frequency (F0)
and frequency derivative (F1). With some of the younger and more "erratic"
pulsars, F2 (and further) can be modelled.

Here's some data on the Vela pulsar (hot off the presses - measured just
now):

F0              11.1867488542579
F1              -1.55859177352837e-11
F2              1.23776878287221e-21

Vela is young and erratic. Millisecond pulsars are outstanding clocks.
Here's the data for J0437-4715 - one of the most stable pulsars we know
about:

F0              173.6879458121843
F1              -1.728361E-15

I'm sure the "Q" of Vela would be pretty decent - but I can tell you now,
as a time-keeper, she's useless.

Jim Palfreyman

On 28 July 2016 at 20:50, Tony Finch dot@dotat.at wrote:

Neville Michie namichie@gmail.com wrote:

The conical pendulum has a simple form of a weight on a string, instead
of oscillating in one plane as a conventional pendulum, it swings around
in a circular orbit in the horizontal plane. It has a definite resonant
frequency.

I don't think it does have a resonant frequency, any more than the Earth
does: the angular velocity of the pendulum is sqrt(g/h) where h is the
height of the pendulum; give it more energy, it swings higher, so h is
smaller, so the frequency is higher.

Tony.

f.anthony.n.finch  dot@dotat.at  http://dotat.at/  -  I xn--zr8h
punycode
South Thames, Dover: Southwesterly 5 or 6. Slight or moderate. Rain or
showers. Good, occasionally poor.


time-nuts mailing list -- time-nuts@febo.com
To unsubscribe, go to
https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts
and follow the instructions there.


time-nuts mailing list -- time-nuts@febo.com
To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts
and follow the instructions there.

What about an ADEV/TDEV plot of the pulsar J0437-4715? On Fri, Jul 29, 2016 at 12:39 AM, Jim Palfreyman <jim77742@gmail.com> wrote: > Hi All, > > Tom gave me a nudge to look here - I hadn't been following this thread. > > For those that don't know, I study pulsars and so the way we measure what > pulsars do could be relevant to this discussion. > > First, I have never heard of a Q measure when referencing a pulsar. I think > the key here is that it's not resonating as such. Rotating yes, resonating > no. > > Pulsars spin and slow down due to giving off energy (magnetic dipole > radiation). So in the pulsar world we mainly refer to spin frequency (F0) > and frequency derivative (F1). With some of the younger and more "erratic" > pulsars, F2 (and further) can be modelled. > > Here's some data on the Vela pulsar (hot off the presses - measured just > now): > > F0 11.1867488542579 > F1 -1.55859177352837e-11 > F2 1.23776878287221e-21 > > Vela is young and erratic. Millisecond pulsars are outstanding clocks. > Here's the data for J0437-4715 - one of the most stable pulsars we know > about: > > F0 173.6879458121843 > F1 -1.728361E-15 > > I'm sure the "Q" of Vela would be pretty decent - but I can tell you now, > as a time-keeper, she's useless. > > > Jim Palfreyman > > > > On 28 July 2016 at 20:50, Tony Finch <dot@dotat.at> wrote: > >> Neville Michie <namichie@gmail.com> wrote: >> >> > The conical pendulum has a simple form of a weight on a string, instead >> > of oscillating in one plane as a conventional pendulum, it swings around >> > in a circular orbit in the horizontal plane. It has a definite resonant >> > frequency. >> >> I don't think it does have a resonant frequency, any more than the Earth >> does: the angular velocity of the pendulum is sqrt(g/h) where h is the >> height of the pendulum; give it more energy, it swings higher, so h is >> smaller, so the frequency is higher. >> >> Tony. >> -- >> f.anthony.n.finch <dot@dotat.at> http://dotat.at/ - I xn--zr8h >> punycode >> South Thames, Dover: Southwesterly 5 or 6. Slight or moderate. Rain or >> showers. Good, occasionally poor. >> _______________________________________________ >> time-nuts mailing list -- time-nuts@febo.com >> To unsubscribe, go to >> https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts >> and follow the instructions there. >> > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there.
D
David
Fri, Jul 29, 2016 8:29 AM

On Wed, 27 Jul 2016 15:15:48 -0400, you wrote:

On 7/27/2016 10:04 AM, time-nuts-request@febo.com wrote:

Exciting the Earth with a new frequency (and an adeguate amount of
energy) sets a new rotational speed: you cannot retune a (for example)
quartz crystal in the same way...

Sure you can. Spin it at 100 RPM, or 1000, RPM or even 25000  RPM... :)

Interesting conversation. I tend to agree the earth is not a classic
harmonic oscillator. Energy is not exchanged between different storage
mechanisms. It's rotational period has no natural harmonic frequency.
i.e. rotational period could be anything.

However I also agree it exhibits characteristics of other items that Q
can be calculated for. Rate of slowing, loss of energy per cycle, etc.
And since the definition of Q is varied and used quite widely, it seems
Q is also appropriate here.

Maybe Earth is a special case since after all it DID give us the second,
and we DO set our atomic clocks to IT every 6 to 12 months...

...now I'll be thinking of this all night...  ...I think Tom is just
toying with us now...

Dan

Capacitors and inductors have an associated Q while lacking a resonate
frequency except for parasitic elements.  Their Q increases with
frequency up to a point; does that apply to a spinning body?  I guess
it depends on the loss mechanism.

If you used the Earth's rotation as part of a harmonic oscillator,
what would limit the Q?  All the sloshing fluid, physical
displacement, and mechanical hysteresis add up to energy lost per
cycle.

This seems like one of those fun physics problems where you start with
a bunch of seemingly unrelated pieces of numerical data and calculate
the mass of the Milky Way.

On Wed, 27 Jul 2016 15:15:48 -0400, you wrote: >On 7/27/2016 10:04 AM, time-nuts-request@febo.com wrote: > >> Exciting the Earth with a new frequency (and an adeguate amount of >> energy) sets a new rotational speed: you cannot retune a (for example) >> quartz crystal in the same way... > >Sure you can. Spin it at 100 RPM, or 1000, RPM or even 25000 RPM... :) > >Interesting conversation. I tend to agree the earth is not a classic >harmonic oscillator. Energy is not exchanged between different storage >mechanisms. It's rotational period has no natural harmonic frequency. >i.e. rotational period could be anything. > >However I also agree it exhibits characteristics of other items that Q >can be calculated for. Rate of slowing, loss of energy per cycle, etc. >And since the definition of Q is varied and used quite widely, it seems >Q is also appropriate here. > >Maybe Earth is a special case since after all it DID give us the second, >and we DO set our atomic clocks to IT every 6 to 12 months... > >...now I'll be thinking of this all night... ...I think Tom is just >toying with us now... > >Dan Capacitors and inductors have an associated Q while lacking a resonate frequency except for parasitic elements. Their Q increases with frequency up to a point; does that apply to a spinning body? I guess it depends on the loss mechanism. If you used the Earth's rotation as part of a harmonic oscillator, what would limit the Q? All the sloshing fluid, physical displacement, and mechanical hysteresis add up to energy lost per cycle. This seems like one of those fun physics problems where you start with a bunch of seemingly unrelated pieces of numerical data and calculate the mass of the Milky Way.
AK
Attila Kinali
Fri, Jul 29, 2016 4:28 PM

On Fri, 29 Jul 2016 03:29:27 -0500
David davidwhess@gmail.com wrote:

Capacitors and inductors have an associated Q while lacking a resonate
frequency except for parasitic elements.  Their Q increases with
frequency up to a point; does that apply to a spinning body?  I guess
it depends on the loss mechanism.

The Q of an inductor (or capacitor) is defined at a specific frequency.
You can see it as the Q factor that would be achieved, if the inductor
(capacitor) would be paired up with an ideal capacitor (inductor) with
a value such, that it would result in the specified frequency.

Hence, if you increase the frequency, the Q factor increases for an inductor. Conversly, the Q factor of an capacitor decreases with increasing  frequency.

See also:
https://en.wikipedia.org/wiki/Inductor#Q_factor
https://en.wikipedia.org/wiki/Capacitor#Q_factor

		Attila Kinali

--
It is upon moral qualities that a society is ultimately founded. All
the prosperity and technological sophistication in the world is of no
use without that foundation.
-- Miss Matheson, The Diamond Age, Neil Stephenson

On Fri, 29 Jul 2016 03:29:27 -0500 David <davidwhess@gmail.com> wrote: > Capacitors and inductors have an associated Q while lacking a resonate > frequency except for parasitic elements. Their Q increases with > frequency up to a point; does that apply to a spinning body? I guess > it depends on the loss mechanism. The Q of an inductor (or capacitor) is defined at a specific frequency. You can see it as the Q factor that would be achieved, if the inductor (capacitor) would be paired up with an ideal capacitor (inductor) with a value such, that it would result in the specified frequency. Hence, if you increase the frequency, the Q factor increases for an inductor. Conversly, the Q factor of an capacitor decreases with increasing frequency. See also: https://en.wikipedia.org/wiki/Inductor#Q_factor https://en.wikipedia.org/wiki/Capacitor#Q_factor Attila Kinali -- It is upon moral qualities that a society is ultimately founded. All the prosperity and technological sophistication in the world is of no use without that foundation. -- Miss Matheson, The Diamond Age, Neil Stephenson
AP
Alex Pummer
Fri, Jul 29, 2016 4:56 PM

the Q factor could be derived from the modulation bandwidth of an
oscillator [ the "old way" of measuring the Q of resonator of the
running oscillator's ], therefore if we look the fluctuation spectrum of
the frequency of an oscillator we could determine the Q. Any circular
movement could be seen as the source of a harmonic oscillation.

73
KJ6UHN
Alex

On 7/29/2016 9:28 AM, Attila Kinali wrote:

On Fri, 29 Jul 2016 03:29:27 -0500
David davidwhess@gmail.com wrote:

Capacitors and inductors have an associated Q while lacking a resonate
frequency except for parasitic elements.  Their Q increases with
frequency up to a point; does that apply to a spinning body?  I guess
it depends on the loss mechanism.

The Q of an inductor (or capacitor) is defined at a specific frequency.
You can see it as the Q factor that would be achieved, if the inductor
(capacitor) would be paired up with an ideal capacitor (inductor) with
a value such, that it would result in the specified frequency.

Hence, if you increase the frequency, the Q factor increases for an inductor. Conversly, the Q factor of an capacitor decreases with increasing  frequency.

See also:
https://en.wikipedia.org/wiki/Inductor#Q_factor
https://en.wikipedia.org/wiki/Capacitor#Q_factor

		Attila Kinali
the Q factor could be derived from the modulation bandwidth of an oscillator [ the "old way" of measuring the Q of resonator of the running oscillator's ], therefore if we look the fluctuation spectrum of the frequency of an oscillator we could determine the Q. Any circular movement could be seen as the source of a harmonic oscillation. 73 KJ6UHN Alex On 7/29/2016 9:28 AM, Attila Kinali wrote: > On Fri, 29 Jul 2016 03:29:27 -0500 > David <davidwhess@gmail.com> wrote: > >> Capacitors and inductors have an associated Q while lacking a resonate >> frequency except for parasitic elements. Their Q increases with >> frequency up to a point; does that apply to a spinning body? I guess >> it depends on the loss mechanism. > The Q of an inductor (or capacitor) is defined at a specific frequency. > You can see it as the Q factor that would be achieved, if the inductor > (capacitor) would be paired up with an ideal capacitor (inductor) with > a value such, that it would result in the specified frequency. > > Hence, if you increase the frequency, the Q factor increases for an inductor. Conversly, the Q factor of an capacitor decreases with increasing frequency. > > See also: > https://en.wikipedia.org/wiki/Inductor#Q_factor > https://en.wikipedia.org/wiki/Capacitor#Q_factor > > > Attila Kinali >
JP
Jim Palfreyman
Sat, Jul 30, 2016 12:24 AM

What about an ADEV/TDEV plot of the pulsar J0437-4715?

Very boring. It's a straight line from top left to bottom right. :-)

See page 5 of this: http://arxiv.org/pdf/1004.0115.pdf

Jim Palfreyman

On 29 July 2016 at 17:33, Azelio Boriani azelio.boriani@gmail.com wrote:

What about an ADEV/TDEV plot of the pulsar J0437-4715?

On Fri, Jul 29, 2016 at 12:39 AM, Jim Palfreyman jim77742@gmail.com
wrote:

Hi All,

Tom gave me a nudge to look here - I hadn't been following this thread.

For those that don't know, I study pulsars and so the way we measure what
pulsars do could be relevant to this discussion.

First, I have never heard of a Q measure when referencing a pulsar. I

think

the key here is that it's not resonating as such. Rotating yes,

resonating

no.

Pulsars spin and slow down due to giving off energy (magnetic dipole
radiation). So in the pulsar world we mainly refer to spin frequency (F0)
and frequency derivative (F1). With some of the younger and more

"erratic"

pulsars, F2 (and further) can be modelled.

Here's some data on the Vela pulsar (hot off the presses - measured just
now):

F0              11.1867488542579
F1              -1.55859177352837e-11
F2              1.23776878287221e-21

Vela is young and erratic. Millisecond pulsars are outstanding clocks.
Here's the data for J0437-4715 - one of the most stable pulsars we know
about:

F0              173.6879458121843
F1              -1.728361E-15

I'm sure the "Q" of Vela would be pretty decent - but I can tell you now,
as a time-keeper, she's useless.

Jim Palfreyman

On 28 July 2016 at 20:50, Tony Finch dot@dotat.at wrote:

Neville Michie namichie@gmail.com wrote:

The conical pendulum has a simple form of a weight on a string,

instead

of oscillating in one plane as a conventional pendulum, it swings

around

in a circular orbit in the horizontal plane. It has a definite

resonant

frequency.

I don't think it does have a resonant frequency, any more than the Earth
does: the angular velocity of the pendulum is sqrt(g/h) where h is the
height of the pendulum; give it more energy, it swings higher, so h is
smaller, so the frequency is higher.

Tony.

f.anthony.n.finch  dot@dotat.at  http://dotat.at/  -  I xn--zr8h
punycode
South Thames, Dover: Southwesterly 5 or 6. Slight or moderate. Rain or
showers. Good, occasionally poor.


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> What about an ADEV/TDEV plot of the pulsar J0437-4715? Very boring. It's a straight line from top left to bottom right. :-) See page 5 of this: http://arxiv.org/pdf/1004.0115.pdf Jim Palfreyman On 29 July 2016 at 17:33, Azelio Boriani <azelio.boriani@gmail.com> wrote: > What about an ADEV/TDEV plot of the pulsar J0437-4715? > > On Fri, Jul 29, 2016 at 12:39 AM, Jim Palfreyman <jim77742@gmail.com> > wrote: > > Hi All, > > > > Tom gave me a nudge to look here - I hadn't been following this thread. > > > > For those that don't know, I study pulsars and so the way we measure what > > pulsars do could be relevant to this discussion. > > > > First, I have never heard of a Q measure when referencing a pulsar. I > think > > the key here is that it's not resonating as such. Rotating yes, > resonating > > no. > > > > Pulsars spin and slow down due to giving off energy (magnetic dipole > > radiation). So in the pulsar world we mainly refer to spin frequency (F0) > > and frequency derivative (F1). With some of the younger and more > "erratic" > > pulsars, F2 (and further) can be modelled. > > > > Here's some data on the Vela pulsar (hot off the presses - measured just > > now): > > > > F0 11.1867488542579 > > F1 -1.55859177352837e-11 > > F2 1.23776878287221e-21 > > > > Vela is young and erratic. Millisecond pulsars are outstanding clocks. > > Here's the data for J0437-4715 - one of the most stable pulsars we know > > about: > > > > F0 173.6879458121843 > > F1 -1.728361E-15 > > > > I'm sure the "Q" of Vela would be pretty decent - but I can tell you now, > > as a time-keeper, she's useless. > > > > > > Jim Palfreyman > > > > > > > > On 28 July 2016 at 20:50, Tony Finch <dot@dotat.at> wrote: > > > >> Neville Michie <namichie@gmail.com> wrote: > >> > >> > The conical pendulum has a simple form of a weight on a string, > instead > >> > of oscillating in one plane as a conventional pendulum, it swings > around > >> > in a circular orbit in the horizontal plane. It has a definite > resonant > >> > frequency. > >> > >> I don't think it does have a resonant frequency, any more than the Earth > >> does: the angular velocity of the pendulum is sqrt(g/h) where h is the > >> height of the pendulum; give it more energy, it swings higher, so h is > >> smaller, so the frequency is higher. > >> > >> Tony. > >> -- > >> f.anthony.n.finch <dot@dotat.at> http://dotat.at/ - I xn--zr8h > >> punycode > >> South Thames, Dover: Southwesterly 5 or 6. Slight or moderate. Rain or > >> showers. Good, occasionally poor. > >> _______________________________________________ > >> time-nuts mailing list -- time-nuts@febo.com > >> To unsubscribe, go to > >> https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > >> and follow the instructions there. > >> > > _______________________________________________ > > time-nuts mailing list -- time-nuts@febo.com > > To unsubscribe, go to > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > > and follow the instructions there. > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there. >